0.03.714.18+0.47+5.9
0.13.734.08+0.35+4.4
0.23.573.51-0.06-0.8
0.33.243.25+0.01+0.1
0.44.334.09-0.24-2.8
0.53.282.84-0.44-7.1
0.64.103.26-0.84-11.4
0.74.183.21-0.97-13.1
0.83.452.46-0.99-16.7
0.93.972.59-1.38-21.0
1.03.582.32-1.26-21.3
data processing
Calculation to find the change in mass of the murphyes at 0.0 mols of saccharose (for example):
4.18 3.71=+0.47
Calculation to find the percentage change in mass of white potatoes at 0.0 mols of sucrose (for example):
((4.18 3.71)/ (4.18+3.71) ×100= +5.9%
Conclusion
The research head word that I asked myself before the experiment was What is the osmotic dominance of potato? The answer I got after the experiment was that the osmotic potential of potato is very high because this experiment exactly showed what happened when in that respect is Osmosis present and the following information will prove it. Our results greatly showed that there has been osmosis present.
Osmosis is the dissemination of water through a partly permeable membrane from a region of lower solute ingress to a region of high solute concentration. And the results we got shows that osmosis occurred in this experiment. In 0.0 mols of sucrose the mass of potato has increased so there has been diffusion of water from 0.0 mols of sucrose which is the lower concentration to 3.71 grams of potato which is the higher concentration. Also in 1.0 mols of sucrose the mass of potato has fall and it should decrease when there is osmosis present because in this case 1.0 mols of sucrose is the higher concentration and the 3.58 grams of potato is the lower concentration. Basically the potato chips lose more mass in the higher arduous solution and gain mass in the lower laborious solution....If you want to get a full essay, order it on our website: Orderessay
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